Display Date Dos Bat File

If, after reading the other questions and viewing the links mentioned in the comment sections, you still can't figure it out, read on. First of all, where you're going wrong is the offset.

It should look more like this. Putt Putt Saves The Zoo Game. Set mydate=!date:~10,4!!date:~6,2!/!date:~4,2! Echo%mydate% If the date was Tue then it would display it as 2013/02/12.

To remove the slashes, the code would look more like set mydate=!date:~10,4!!date:~7,2!!date:~4,2! Which would output 20130212, which doesn't look anything like a date. And a hint for doing it in the future, if mydate equals something like!date:~10,4!!date:~7,2!

I discovered the following tech-recipe while working on a some old dos batch files. This tutorial describes a simple.bat file used to create a folder based on the. I have been using the following command to get the file date. However, the fileDate variable has been returning blank value ever since we moved to a different server. Click 'File' and then 'Save.' Enter 'my_batch.bat' and click 'OK.' Click 'File' and then 'Exit.' Type in 'my_batch. Bijoy Bayanno Unicode Keyboard Layout. bat' and press 'Enter' to display the current date and time on the computer screen.